Oracle-like ROWNUM in MySQL

March 28, 2009 · Leave a Comment
Filed under: Featured, MySql, MySQL 5.1, Oracle 

 

It needs sometimes to exactly mimic Oracle’s ROWNUM where is no possibility to initiate a counter in previous statement by SET @rownum:=0;.




It is still possible in a single SQL.

SELECT @rownum:=@rownum+1 rownum, t.*FROM (SELECT @rownum:=0) r, mytable t;

 

SQL JOINS

February 13, 2009 · Leave a Comment
Filed under: Featured, MySql, MySQL 5.1, Oracle, SQL, SQL JOINS 

 

The SQL JOIN clause is used whenever we have to select data from 2 or more tables.

To be able to use SQL JOIN clause to extract data from 2 (or more) tables, we need a relationship between certain columns in these tables.

We are going to illustrate our SQL JOIN example with the following 2 tables:

Customers:

CustomerID

FirstName

LastName

Email

DOB

Phone

1

John

Smith

John.Smith@yahoo.com

2/4/1968

626 222-2222

2

Steven

Goldfish

goldfish@fishhere.net

4/4/1974

323 455-4545

3

Paula

Brown

pb@herowndomain.org

5/24/1978

416 323-3232

4

James

Smith

jim@supergig.co.uk

20/10/1980

416 323-8888

Sales:

CustomerID

Date

SaleAmount

2

5/6/2004

$100.22

1

5/7/2004

$99.95

3

5/7/2004

$122.95

3

5/13/2004

$100.00

4

5/22/2004

$555.55

As you can see those 2 tables have common field called CustomerID and thanks to that we can extract information from both tables by matching their CustomerID columns.

Consider the following SQL statement:

SELECT Customers.FirstName, Customers.LastName, SUM(Sales.SaleAmount) AS SalesPerCustomer
FROM Customers, Sales
WHERE Customers.CustomerID = Sales.CustomerID
GROUP BY Customers.FirstName, Customers.LastName

The SQL expression above will select all distinct customers (their first and last names) and the total respective amount of dollars they have spent.
The SQL JOIN condition has been specified after the SQL WHERE clause and says that the 2 tables have to be matched by their respective CustomerID columns.

Here is the result of this SQL statement:

FirstName

LastName

SalesPerCustomers

John

Smith

$99.95

Steven

Goldfish

$100.22

Paula

Brown

$222.95

James

Smith

$555.55

The SQL statement above can be re-written using the SQL JOIN clause like this:

SELECT Customers.FirstName, Customers.LastName, SUM(Sales.SaleAmount) AS SalesPerCustomer
FROM Customers JOIN Sales
ON Customers.CustomerID = Sales.CustomerID
GROUP BY Customers.FirstName, Customers.LastName

There are 2 types of SQL JOINS – INNER JOINS and OUTER JOINS. If you don’t put INNER or OUTER keywords in front of the SQL JOIN keyword, then INNER JOIN is used. In short “INNER JOIN” = “JOIN” (note that different databases have different syntax for their JOIN clauses).

The INNER JOIN will select all rows from both tables as long as there is a match between the columns we are matching on. In case we have a customer in the Customers table, which still hasn’t made any orders (there are no entries for this customer in the Sales table), this customer will not be listed in the result of our SQL query above.

If the Sales table has the following rows:

CustomerID

Date

SaleAmount

2

5/6/2004

$100.22

1

5/6/2004

$99.95

And we use the same SQL JOIN statement from above:

SELECT Customers.FirstName, Customers.LastName, SUM(Sales.SaleAmount) AS SalesPerCustomer
FROM Customers JOIN Sales
ON Customers.CustomerID = Sales.CustomerID
GROUP BY Customers.FirstName, Customers.LastName

We’ll get the following result:

FirstName

LastName

SalesPerCustomers

John

Smith

$99.95

Steven

Goldfish

$100.22

Even though Paula and James are listed as customers in the Customers table they won’t be displayed because they haven’t purchased anything yet.

But what if you want to display all the customers and their sales, no matter if they have ordered something or not? We’ll do that with the help of SQL OUTER JOIN clause.

The second type of SQL JOIN is called SQL OUTER JOIN and it has 2 sub-types called LEFT OUTER JOIN and RIGHT OUTER JOIN.

The LEFT OUTER JOIN or simply LEFT JOIN (you can omit the OUTER keyword in most databases), selects all the rows from the first table listed after the FROM clause, no matter if they have matches in the second table.

If we slightly modify our last SQL statement to:

SELECT Customers.FirstName, Customers.LastName, SUM(Sales.SaleAmount) AS SalesPerCustomer
FROM Customers LEFT JOIN Sales
ON Customers.CustomerID = Sales.CustomerID
GROUP BY Customers.FirstName, Customers.LastName

and the Sales table still has the following rows:

CustomerID

Date

SaleAmount

2

5/6/2004

$100.22

1

5/6/2004

$99.95

The result will be the following:

FirstName

LastName

SalesPerCustomers

John

Smith

$99.95

Steven

Goldfish

$100.22

Paula

Brown

NULL

James

Smith

NULL

As you can see we have selected everything from the Customers (first table). For all rows from Customers, which don’t have a match in the Sales (second table), the SalesPerCustomer column has amount NULL (NULL means a column contains nothing).

The RIGHT OUTER JOIN or just RIGHT JOIN behaves exactly as SQL LEFT JOIN, except that it returns all rows from the second table (the right table in our SQL JOIN statement).

interesting?..http://www.devshed.com/c/a/MySQL/Understanding-SQL-Joins/

 

 

 

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